What are the solutions to the equation 3x^2+2=7x ?

The solutions to the equation 3x^2+2=7x are x=2,x= 1/3

Find the zeros of 3x^2+2=7x

The zeros of 3x^2+2=7x are x=2,x= 1/3

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3 x^{2} + 2 = 7 x

x = 2, x = \frac{1}{3}

Decimal Notation

x = 2, x = 0.33333 \dots

Solution steps

3 x^{2} + 2 = 7 x

Move

7 x

to the left side

3 x^{2} + 2 - 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 7 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

(- 7)^{2} - 4 \cdot 3 \cdot 2 = 5

x_{1, 2} = \frac{- ( - 7 ) \pm 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 5}{2 \cdot 3}, x_{2} = \frac{- ( - 7 ) - 5}{2 \cdot 3}

x = \frac{- ( - 7 ) + 5}{2 \cdot 3} : 2

x = \frac{- ( - 7 ) - 5}{2 \cdot 3} : \frac{1}{3}

The solutions to the quadratic equation are:

x = 2, x = \frac{1}{3}

2 (\frac{x}{3} + 5) = \frac{2 x}{4} + 4

3 x = \frac{1}{2} - 9 + \frac{3}{2}

x - 4 = 2

- 4 x + 7 > - 25 or 7 x + 2 \geq - 19

ln (\frac{x}{x - 9}) + ln (\frac{x + 9}{x}) - ln (x^{2} - 81)

What are the solutions to the equation 3x^2+2=7x ?
The solutions to the equation 3x^2+2=7x are x=2,x= 1/3
Find the zeros of 3x^2+2=7x
The zeros of 3x^2+2=7x are x=2,x= 1/3