What is (k(4-k))/4 >0 ?

The solution to (k(4-k))/4 >0 is 0<k<4

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(k(4-k))/4 >0

\frac{k ( 4 - k )}{4} > 0

0 < k < 4

Interval Notation

(0, 4)

Solution steps

\frac{k ( 4 - k )}{4} > 0

Rewrite in standard form

4 k - k^{2} > 0

Factor

4 k - k^{2} : - k (k - 4)

- k (k - 4) > 0

Multiply both sides by

- 1

(reverse the inequality)

(- k (k - 4)) (- 1) < 0 \cdot (- 1)

Simplify

k (k - 4) < 0

Identify the intervals

0 < k < 4

\frac{7 i}{4 + 4 i}

2 x - 2 (3 x - 5) < x

x^{2} + 11 x + 32 = 0

3 r^{2} - 8 r + 5

14 t - 28 < 7 (t + 6)