What is (x+4}{-2}<= \frac{3x-8)/3 ?

The solution to (x+4}{-2}<= \frac{3x-8)/3 is x<= 4/9

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(x+4}{-2}<= \frac{3x-8)/3

\frac{x + 4}{- 2} \leq \frac{3 x - 8}{3}

x \leq \frac{4}{9}

Interval Notation

(- \infty, \frac{4}{9}]

Decimal Notation

x \leq 0.44444 \dots

Solution steps

\frac{x + 4}{- 2} \leq \frac{3 x - 8}{3}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(x + 4) \cdot 3 \leq (- 2) (3 x - 8)

Simplify

(x + 4) \cdot 3 \leq - 2 (3 x - 8)

Expand

(x + 4) \cdot 3 : 3 x + 12

Expand

- 2 (3 x - 8) : - 6 x + 16

3 x + 12 \leq - 6 x + 16

Move

12

to the right side

3 x \leq - 6 x + 4

Move

6 x

to the left side

9 x \leq 4

Divide both sides by

9

x \leq \frac{4}{9}

2 x^{2} - 19 x - 33 = 0

(2 x + 3) (2 x - 3) + 5 x = 2 (x + 1) - 1

x^{4} - x^{3} - 13 x^{2} + x + 12

3 x^{2} + 25 x + 8

6 \leq 6

What is (x+4}{-2}<= \frac{3x-8)/3 ?
The solution to (x+4}{-2}<= \frac{3x-8)/3 is x<= 4/9