What are the solutions to the equation x^2-4x-6=0 ?

The solutions to the equation x^2-4x-6=0 are x=2+sqrt(10),x=2-sqrt(10)

Find the zeros of x^2-4x-6=0

The zeros of x^2-4x-6=0 are x=2+sqrt(10),x=2-sqrt(10)

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x^{2} - 4 x - 6 = 0

x = 2 + 10, x = 2 - 10

Decimal Notation

x = 5.16227 \dots, x = - 1.16227 \dots

Solution steps

x^{2} - 4 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 6) = 210

x_{1, 2} = \frac{- ( - 4 ) \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 10}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 10}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 10}{2 \cdot 1} : 2 + 10

x = \frac{- ( - 4 ) - 2 10}{2 \cdot 1} : 2 - 10

The solutions to the quadratic equation are:

x = 2 + 10, x = 2 - 10

\frac{36 6 ^{365}}{36 5 ^{365}}

- 2 x^{2} - 3 x + 4 = 0

- 72 + 6 w + w^{2}

a^{2} - a - 20 = 0

1 + x \geq 2 x

What are the solutions to the equation x^2-4x-6=0 ?
The solutions to the equation x^2-4x-6=0 are x=2+sqrt(10),x=2-sqrt(10)
Find the zeros of x^2-4x-6=0
The zeros of x^2-4x-6=0 are x=2+sqrt(10),x=2-sqrt(10)