What are the solutions to the equation 3-2x-x^2=0 ?

The solutions to the equation 3-2x-x^2=0 are x=-3,x=1

Find the zeros of 3-2x-x^2=0

The zeros of 3-2x-x^2=0 are x=-3,x=1

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3 - 2 x - x^{2} = 0

x = - 3, x = 1

Solution steps

3 - 2 x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} - 2 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) \cdot 3}{2 ( - 1 )}

(- 2)^{2} - 4 (- 1) \cdot 3 = 4

x_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4}{2 ( - 1 )}, x_{2} = \frac{- ( - 2 ) - 4}{2 ( - 1 )}

x = \frac{- ( - 2 ) + 4}{2 ( - 1 )} : - 3

x = \frac{- ( - 2 ) - 4}{2 ( - 1 )} : 1

The solutions to the quadratic equation are:

x = - 3, x = 1

7 x^{2} - 14 x - 21

\frac{- x}{4} - \frac{x}{3} = 14

15 \cdot 6 \cdot 12 \cdot 1 0^{- 2}

4 (x - 2) = x + 10

2^{n} < 60000 \cdot 60 \cdot 24

What are the solutions to the equation 3-2x-x^2=0 ?
The solutions to the equation 3-2x-x^2=0 are x=-3,x=1
Find the zeros of 3-2x-x^2=0
The zeros of 3-2x-x^2=0 are x=-3,x=1