What is ((2p^3k^{-3})^{-5})/(10k^{-6)} ?

The solution to ((2p^3k^{-3})^{-5})/(10k^{-6)} is (k^{21})/(320p^{15)}

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simplify ((2p^3k^{-3})^{-5})/(10k^{-6)}

simplify

\frac{( 2 p ^{3} k ^{- 3} ) ^{- 5}}{10 k ^{- 6}}

\frac{k ^{21}}{320 p ^{15}}

Solution steps

\frac{( 2 p ^{3} k ^{- 3} ) ^{- 5}}{10 k ^{- 6}}

Simplify

(2 p^{3} k^{- 3})^{- 5} : 2^{- 5} \cdot \frac{1}{p ^{15}} k^{15}

= \frac{2 ^{- 5} \cdot \frac{1}{p ^{15}} k ^{15}}{10 k ^{- 6}}

Factor the number:

10 = 2 \cdot 5

= \frac{2 ^{- 5} \cdot \frac{1}{p ^{15}} k ^{15}}{2 \cdot 5 k ^{- 6}}

\frac{2 ^{- 5}}{2} = \frac{1}{2 ^{6}}

= \frac{\frac{1}{p ^{15}} k ^{15}}{2 ^{6} \cdot 5 k ^{- 6}}

Simplify

\frac{k ^{15}}{k ^{- 6}} : k^{21}

= \frac{\frac{1}{p ^{15}} k ^{21}}{2 ^{6} \cdot 5}

Simplify

\frac{\frac{1}{p ^{15}} k ^{21}}{2 ^{6} \cdot 5} : \frac{k ^{21}}{p ^{15} \cdot 320}

= \frac{k ^{21}}{p ^{15} \cdot 320}

= \frac{k ^{21}}{320 p ^{15}}

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7 y + 21

\frac{1}{3} - \frac{1}{4}

What is ((2p^3k^{-3})^{-5})/(10k^{-6)} ?
The solution to ((2p^3k^{-3})^{-5})/(10k^{-6)} is (k^{21})/(320p^{15)}