What are the solutions to the equation x^2+4=56 ?

The solutions to the equation x^2+4=56 are x=2sqrt(13),x=-2sqrt(13)

Find the zeros of x^2+4=56

The zeros of x^2+4=56 are x=2sqrt(13),x=-2sqrt(13)

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x^{2} + 4 = 56

x = 213, x = - 213

Decimal Notation

x = 7.21110 \dots, x = - 7.21110 \dots

Solution steps

x^{2} + 4 = 56

Move

4

to the right side

x^{2} = 52

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 52, x = - 52

52 = 213

- 52 = - 213

x = 213, x = - 213

b^{- 6} \cdot b^{11}

\frac{3}{4} (2 a - b) - \frac{2}{3} (a - 2 b)

\frac{6 x ^{3} + 8 x ^{2} - 15 x - 20}{16 x ^{2} - 64} \geq 0

14 + 3 n = 8 n - 3 (n - 4)

10 x + 15 = 9 (9)

What are the solutions to the equation x^2+4=56 ?
The solutions to the equation x^2+4=56 are x=2sqrt(13),x=-2sqrt(13)
Find the zeros of x^2+4=56
The zeros of x^2+4=56 are x=2sqrt(13),x=-2sqrt(13)