What are the solutions to the equation 2x^2+32x=0 ?

The solutions to the equation 2x^2+32x=0 are x=0,x=-16

Find the zeros of 2x^2+32x=0

The zeros of 2x^2+32x=0 are x=0,x=-16

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2 x^{2} + 32 x = 0

x = 0, x = - 16

Solution steps

2 x^{2} + 32 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

3 2^{2} - 4 \cdot 2 \cdot 0 = 32

x_{1, 2} = \frac{- 32 \pm 32}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 32 + 32}{2 \cdot 2}, x_{2} = \frac{- 32 - 32}{2 \cdot 2}

x = \frac{- 32 + 32}{2 \cdot 2} : 0

x = \frac{- 32 - 32}{2 \cdot 2} : - 16

The solutions to the quadratic equation are:

x = 0, x = - 16

4 (3 y - 1) = 2 (2 y + 6)

(\frac{- 3 x}{2} + 6)^{2} + x^{2} - 2 x + 5 = 41

(37)^{2}

1 + \frac{1}{x} - \frac{2}{x + 1} < 0

6 a^{2} + 10 a - 4

What are the solutions to the equation 2x^2+32x=0 ?
The solutions to the equation 2x^2+32x=0 are x=0,x=-16
Find the zeros of 2x^2+32x=0
The zeros of 2x^2+32x=0 are x=0,x=-16