What are the solutions to the equation 3(x+1)^2=27 ?

The solutions to the equation 3(x+1)^2=27 are x=2,x=-4

Find the zeros of 3(x+1)^2=27

The zeros of 3(x+1)^2=27 are x=2,x=-4

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3 (x + 1)^{2} = 27

x = 2, x = - 4

Solution steps

3 (x + 1)^{2} = 27

Divide both sides by

3

(x + 1)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 9 : x = 2

Solve

x + 1 = - 9 : x = - 4

The solutions to the quadratic equation are:

x = 2, x = - 4

0.05 \cdot 5

- 8 > x - 3

2 n^{2} = 6

\frac{x}{3} - 4 = x - 10

30 (e^{2} 2 + \frac{e ^{2}}{2 2})

What are the solutions to the equation 3(x+1)^2=27 ?
The solutions to the equation 3(x+1)^2=27 are x=2,x=-4
Find the zeros of 3(x+1)^2=27
The zeros of 3(x+1)^2=27 are x=2,x=-4