What are the solutions to the equation 2(x+2)^2=36 ?

The solutions to the equation 2(x+2)^2=36 are x=3sqrt(2)-2,x=-3sqrt(2)-2

Find the zeros of 2(x+2)^2=36

The zeros of 2(x+2)^2=36 are x=3sqrt(2)-2,x=-3sqrt(2)-2

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2 (x + 2)^{2} = 36

x = 32 - 2, x = - 32 - 2

Decimal Notation

x = 2.24264 \dots, x = - 6.24264 \dots

Solution steps

2 (x + 2)^{2} = 36

Divide both sides by

2

(x + 2)^{2} = 18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 18 : x = 32 - 2

Solve

x + 2 = - 18 : x = - 32 - 2

The solutions to the quadratic equation are:

x = 32 - 2, x = - 32 - 2

p^{3} - 25 p \leq 0

\frac{1}{30} q^{2} - \frac{3}{10} q - 0.55 = 0

\frac{3 b - 6}{b ^{2} - 4}

∣ 2 x - 3 ∣ \leq 8

- 3 (x + 2) = 3 x - 3

What are the solutions to the equation 2(x+2)^2=36 ?
The solutions to the equation 2(x+2)^2=36 are x=3sqrt(2)-2,x=-3sqrt(2)-2
Find the zeros of 2(x+2)^2=36
The zeros of 2(x+2)^2=36 are x=3sqrt(2)-2,x=-3sqrt(2)-2