What are the solutions to the equation (x-6)(x+3)=0 ?

The solutions to the equation (x-6)(x+3)=0 are x=6,x=-3

Find the zeros of (x-6)(x+3)=0

The zeros of (x-6)(x+3)=0 are x=6,x=-3

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(x - 6) (x + 3) = 0

x = 6, x = - 3

Solution steps

(x - 6) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 6 = 0 or x + 3 = 0

Solve

x - 6 = 0 : x = 6

Solve

x + 3 = 0 : x = - 3

The solutions to the quadratic equation are:

x = 6, x = - 3

- \frac{1}{9} - (- \frac{3}{2})

4 x^{2} - 2 x

x^{2} - 8 x + 17 = 0

- 1.8 (3)^{2} + 14.4 (3)

5 x^{2} + 16 x + 3 = 0

What are the solutions to the equation (x-6)(x+3)=0 ?
The solutions to the equation (x-6)(x+3)=0 are x=6,x=-3
Find the zeros of (x-6)(x+3)=0
The zeros of (x-6)(x+3)=0 are x=6,x=-3