What are the solutions to the equation 5d^2+19d+16=0 ?

The solutions to the equation 5d^2+19d+16=0 are d=(-19+sqrt(41))/(10),d=(-19-sqrt(41))/(10)

Find the zeros of 5d^2+19d+16=0

The zeros of 5d^2+19d+16=0 are d=(-19+sqrt(41))/(10),d=(-19-sqrt(41))/(10)

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5 d^{2} + 19 d + 16 = 0

d = \frac{- 19 + 41}{10}, d = \frac{- 19 - 41}{10}

Decimal Notation

d = - 1.25968 \dots, d = - 2.54031 \dots

Solution steps

5 d^{2} + 19 d + 16 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 5 \cdot 16}{2 \cdot 5}

1 9^{2} - 4 \cdot 5 \cdot 16 = 41

d_{1, 2} = \frac{- 19 \pm 41}{2 \cdot 5}

Separate the solutions

d_{1} = \frac{- 19 + 41}{2 \cdot 5}, d_{2} = \frac{- 19 - 41}{2 \cdot 5}

d = \frac{- 19 + 41}{2 \cdot 5} : \frac{- 19 + 41}{10}

d = \frac{- 19 - 41}{2 \cdot 5} : \frac{- 19 - 41}{10}

The solutions to the quadratic equation are:

d = \frac{- 19 + 41}{10}, d = \frac{- 19 - 41}{10}

12 x^{2} - 24 x + 8

∣ x - 7 ∣ = - 5

x^{2} + 7 x - 98

- 33

n + 3 = 9

What are the solutions to the equation 5d^2+19d+16=0 ?
The solutions to the equation 5d^2+19d+16=0 are d=(-19+sqrt(41))/(10),d=(-19-sqrt(41))/(10)
Find the zeros of 5d^2+19d+16=0
The zeros of 5d^2+19d+16=0 are d=(-19+sqrt(41))/(10),d=(-19-sqrt(41))/(10)