What are the solutions to the equation -0.2y^2+45=0 ?

The solutions to the equation -0.2y^2+45=0 are y=15,y=-15

Find the zeros of -0.2y^2+45=0

The zeros of -0.2y^2+45=0 are y=15,y=-15

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- 0.2 y^{2} + 45 = 0

y = 15, y = - 15

Solution steps

- 0.2 y^{2} + 45 = 0

Move

45

to the right side

- 0.2 y^{2} = - 45

Divide both sides by

- 0.2

y^{2} = 225

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 225, y = - 225

225 = 15

- 225 = - 15

y = 15, y = - 15

4 + 4 3 i

x^{2} - 4 = - 11

6 x + 2 > 4

- 15 + 2 x \geq - 39

(- 8)^{0}

What are the solutions to the equation -0.2y^2+45=0 ?
The solutions to the equation -0.2y^2+45=0 are y=15,y=-15
Find the zeros of -0.2y^2+45=0
The zeros of -0.2y^2+45=0 are y=15,y=-15