What is ((2xy^2)/z+5xz^2+2xyz)(3xy^3-2/z) ?

The solution to ((2xy^2)/z+5xz^2+2xyz)(3xy^3-2/z) is ((2xy^2+5xz^3+2xyz^2)(3xy^3z-2))/(z^2)

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simplify ((2xy^2)/z+5xz^2+2xyz)(3xy^3-2/z)

simplify

(\frac{2 x y ^{2}}{z} + 5 x z^{2} + 2 x yz) (3 x y^{3} - \frac{2}{z})

\frac{( 2 x y ^{2} + 5 x z ^{3} + 2 x y z ^{2} ) ( 3 x y ^{3} z - 2 )}{z ^{2}}

Solution steps

(\frac{2 x y ^{2}}{z} + 5 x z^{2} + 2 x yz) (3 x y^{3} - \frac{2}{z})

Join

\frac{2 x y ^{2}}{z} + 5 x z^{2} + 2 x yz : \frac{2 x y ^{2} + 5 x z ^{3} + 2 x y z ^{2}}{z}

= \frac{2 x y ^{2} + 5 x z ^{3} + 2 x y z ^{2}}{z} (3 x y^{3} - \frac{2}{z})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 2 x y ^{2} + 5 x z ^{3} + 2 x y z ^{2} ) ( 3 x y ^{3} - \frac{2}{z} )}{z}

Simplify

(2 x y^{2} + 5 x z^{3} + 2 x y z^{2}) (3 x y^{3} - \frac{2}{z}) : \frac{( 2 x y ^{2} + 5 x z ^{3} + 2 x y z ^{2} ) ( 3 x y ^{3} z - 2 )}{z}

= \frac{\frac{( 2 x y ^{2} + 5 x z ^{3} + 2 x y z ^{2} ) ( 3 x y ^{3} z - 2 )}{z}}{z}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 2 x y ^{2} + 5 x z ^{3} + 2 x y z ^{2} ) ( 3 x y ^{3} z - 2 )}{zz}

Apply exponent rule:

aa = a^{2}

zz = z^{2}

= \frac{( 2 x y ^{2} + 5 x z ^{3} + 2 x y z ^{2} ) ( 3 x y ^{3} z - 2 )}{z ^{2}}

14 x^{2} - 53 x + 14

14 - 6 (a + 2) = 9 + a

25 a^{2} - 16 b^{2}

2 y^{2} + 11 y + 9

- 2 + 7

What is ((2xy^2)/z+5xz^2+2xyz)(3xy^3-2/z) ?
The solution to ((2xy^2)/z+5xz^2+2xyz)(3xy^3-2/z) is ((2xy^2+5xz^3+2xyz^2)(3xy^3z-2))/(z^2)