What is (-j^4-4j^3-2j^2)-(-2j^4+8j^3+4j^2-8j) ?

The solution to (-j^4-4j^3-2j^2)-(-2j^4+8j^3+4j^2-8j) is j^4-12j^3-6j^2+8j

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (-j^4-4j^3-2j^2)-(-2j^4+8j^3+4j^2-8j)

simplify

(- j^{4} - 4 j^{3} - 2 j^{2}) - (- 2 j^{4} + 8 j^{3} + 4 j^{2} - 8 j)

j^{4} - 12 j^{3} - 6 j^{2} + 8 j

Solution steps

(- j^{4} - 4 j^{3} - 2 j^{2}) - (- 2 j^{4} + 8 j^{3} + 4 j^{2} - 8 j)

Apply rule:

(a) = a

(- j^{4} - 4 j^{3} - 2 j^{2}) = - j^{4} - 4 j^{3} - 2 j^{2}

= - j^{4} - 4 j^{3} - 2 j^{2} - (- 2 j^{4} + 8 j^{3} + 4 j^{2} - 8 j)

Apply the distributive law:

- (- a + b) = a - b

- (- 2 j^{4} + 8 j^{3} + 4 j^{2} - 8 j) = 2 j^{4} - 8 j^{3} - 4 j^{2} + 8 j

= - j^{4} - 4 j^{3} - 2 j^{2} + 2 j^{4} - 8 j^{3} - 4 j^{2} + 8 j

Group like terms

= - j^{4} + 2 j^{4} - 4 j^{3} - 8 j^{3} - 2 j^{2} - 4 j^{2} + 8 j

Add similar elements:

- j^{4} + 2 j^{4} = j^{4}

= j^{4} - 4 j^{3} - 8 j^{3} - 2 j^{2} - 4 j^{2} + 8 j

Add similar elements:

- 4 j^{3} - 8 j^{3} = - 12 j^{3}

= j^{4} - 12 j^{3} - 2 j^{2} - 4 j^{2} + 8 j

Add similar elements:

- 2 j^{2} - 4 j^{2} = - 6 j^{2}

= j^{4} - 12 j^{3} - 6 j^{2} + 8 j

(x - 3)^{2} = 49

\frac{7}{18} \cdot 4

(x - 5) (x + 1) \leq 0

\frac{8 ^{- 2}}{4 ^{0}}

What is (-j^4-4j^3-2j^2)-(-2j^4+8j^3+4j^2-8j) ?
The solution to (-j^4-4j^3-2j^2)-(-2j^4+8j^3+4j^2-8j) is j^4-12j^3-6j^2+8j