What are the solutions to the equation (x+1)^2-1=0 ?

The solutions to the equation (x+1)^2-1=0 are x=0,x=-2

Find the zeros of (x+1)^2-1=0

The zeros of (x+1)^2-1=0 are x=0,x=-2

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(x + 1)^{2} - 1 = 0

x = 0, x = - 2

Solution steps

(x + 1)^{2} - 1 = 0

Move

1

to the right side

(x + 1)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 1 : x = 0

Solve

x + 1 = - 1 : x = - 2

The solutions to the quadratic equation are:

x = 0, x = - 2

∣ 4 x + 5 ∣ > 3

(6^{3})^{4}

20 x = 5

\frac{2 i}{3 - 4 i}

108 g^{2} h - 162 g h + 54 h

What are the solutions to the equation (x+1)^2-1=0 ?
The solutions to the equation (x+1)^2-1=0 are x=0,x=-2
Find the zeros of (x+1)^2-1=0
The zeros of (x+1)^2-1=0 are x=0,x=-2