What are the solutions to the equation x^2+x+8=0 ?

The solutions to the equation x^2+x+8=0 are x=-1/2+i(sqrt(31))/2 ,x=-1/2-i(sqrt(31))/2

Find the zeros of x^2+x+8=0

The zeros of x^2+x+8=0 are x=-1/2+i(sqrt(31))/2 ,x=-1/2-i(sqrt(31))/2

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x^{2} + x + 8 = 0

x = - \frac{1}{2} + i \frac{31}{2}, x = - \frac{1}{2} - i \frac{31}{2}

Solution steps

x^{2} + x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 8 : 31 i

x_{1, 2} = \frac{- 1 \pm 31 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 31 i}{2 \cdot 1}, x_{2} = \frac{- 1 - 31 i}{2 \cdot 1}

x = \frac{- 1 + 31 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{31}{2}

x = \frac{- 1 - 31 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{31}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{31}{2}, x = - \frac{1}{2} - i \frac{31}{2}

5 x^{2} - 22 x + 8

∣ x - 7 ∣ = 5

9 r (z + 1) + 3 r (z + 1)

\frac{7}{x y ^{2}} + \frac{3}{x ^{2} y}

2 x^{2} + 5 x + 1 = 0

What are the solutions to the equation x^2+x+8=0 ?
The solutions to the equation x^2+x+8=0 are x=-1/2+i(sqrt(31))/2 ,x=-1/2-i(sqrt(31))/2
Find the zeros of x^2+x+8=0
The zeros of x^2+x+8=0 are x=-1/2+i(sqrt(31))/2 ,x=-1/2-i(sqrt(31))/2