What are the solutions to the equation x^2+3/4 x+1/8 =0 ?

The solutions to the equation x^2+3/4 x+1/8 =0 are x=-1/4 ,x=-1/2

Find the zeros of x^2+3/4 x+1/8 =0

The zeros of x^2+3/4 x+1/8 =0 are x=-1/4 ,x=-1/2

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x^{2} + \frac{3}{4} x + \frac{1}{8} = 0

x = - \frac{1}{4}, x = - \frac{1}{2}

Decimal Notation

x = - 0.25, x = - 0.5

Solution steps

x^{2} + \frac{3}{4} x + \frac{1}{8} = 0

Find Least Common Multiplier of

4, 8 : 8

Multiply by LCM=

8

x^{2} \cdot 8 + \frac{3}{4} x \cdot 8 + \frac{1}{8} \cdot 8 = 0 \cdot 8

Simplify

8 x^{2} + 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 8 \cdot 1}{2 \cdot 8}

6^{2} - 4 \cdot 8 \cdot 1 = 2

x_{1, 2} = \frac{- 6 \pm 2}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 6 + 2}{2 \cdot 8}, x_{2} = \frac{- 6 - 2}{2 \cdot 8}

x = \frac{- 6 + 2}{2 \cdot 8} : - \frac{1}{4}

x = \frac{- 6 - 2}{2 \cdot 8} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{4}, x = - \frac{1}{2}

x = 2 x + 3

2 i (\frac{1}{2} - i)

∣ x + 1 ∣ + ∣ x - 2 ∣ = 3

\frac{3}{5} (- \frac{60}{3})

3 x - 4 - 3 (x + 5) = - 6 (x + 1)

What are the solutions to the equation x^2+3/4 x+1/8 =0 ?
The solutions to the equation x^2+3/4 x+1/8 =0 are x=-1/4 ,x=-1/2
Find the zeros of x^2+3/4 x+1/8 =0
The zeros of x^2+3/4 x+1/8 =0 are x=-1/4 ,x=-1/2