What are the solutions to the equation x^2-0.632x+0.1=0 ?

The solutions to the equation x^2-0.632x+0.1=0 are x= 79/250+i 3/250 ,x= 79/250-i 3/250

Find the zeros of x^2-0.632x+0.1=0

The zeros of x^2-0.632x+0.1=0 are x= 79/250+i 3/250 ,x= 79/250-i 3/250

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x^{2} - 0.632 x + 0.1 = 0

x = \frac{79}{250} + i \frac{3}{250}, x = \frac{79}{250} - i \frac{3}{250}

Solution steps

x^{2} - 0.632 x + 0.1 = 0

Multiply both sides by

1000

1000 x^{2} - 632 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 632 ) \pm ( - 632 ) ^{2} - 4 \cdot 1000 \cdot 100}{2 \cdot 1000}

Simplify

(- 632)^{2} - 4 \cdot 1000 \cdot 100 : 24 i

x_{1, 2} = \frac{- ( - 632 ) \pm 24 i}{2 \cdot 1000}

Separate the solutions

x_{1} = \frac{- ( - 632 ) + 24 i}{2 \cdot 1000}, x_{2} = \frac{- ( - 632 ) - 24 i}{2 \cdot 1000}

x = \frac{- ( - 632 ) + 24 i}{2 \cdot 1000} : \frac{79}{250} + i \frac{3}{250}

x = \frac{- ( - 632 ) - 24 i}{2 \cdot 1000} : \frac{79}{250} - i \frac{3}{250}

The solutions to the quadratic equation are:

x = \frac{79}{250} + i \frac{3}{250}, x = \frac{79}{250} - i \frac{3}{250}

n^{2} - 1

x \frac{2}{3} - 3 x \frac{1}{3} = 28

3 (x - 2) - 5 > 4 x

1 2^{2} + 9^{2}

13 x - 5 = - 5 + 13 x

What are the solutions to the equation x^2-0.632x+0.1=0 ?
The solutions to the equation x^2-0.632x+0.1=0 are x= 79/250+i 3/250 ,x= 79/250-i 3/250
Find the zeros of x^2-0.632x+0.1=0
The zeros of x^2-0.632x+0.1=0 are x= 79/250+i 3/250 ,x= 79/250-i 3/250