What are the solutions to the equation 7x^2=x^2+7 ?

The solutions to the equation 7x^2=x^2+7 are x=sqrt(7/6),x=-sqrt(7/6)

Find the zeros of 7x^2=x^2+7

The zeros of 7x^2=x^2+7 are x=sqrt(7/6),x=-sqrt(7/6)

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7 x^{2} = x^{2} + 7

x = \frac{7}{6}, x = - \frac{7}{6}

Decimal Notation

x = 1.08012 \dots, x = - 1.08012 \dots

Solution steps

7 x^{2} = x^{2} + 7

Move

x^{2}

to the left side

6 x^{2} = 7

Divide both sides by

6

x^{2} = \frac{7}{6}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{7}{6}, x = - \frac{7}{6}

x^{2} e^{x} - 3 e^{x} < 0

∣ x + 7 ∣ < 2

\frac{2}{2 3}

1 - 64 m^{3}

5 x^{2} + x + 2 = 0

What are the solutions to the equation 7x^2=x^2+7 ?
The solutions to the equation 7x^2=x^2+7 are x=sqrt(7/6),x=-sqrt(7/6)
Find the zeros of 7x^2=x^2+7
The zeros of 7x^2=x^2+7 are x=sqrt(7/6),x=-sqrt(7/6)