What is factor ((2x^4-6x^2+4x))/((6x^4-12x^3+6x^2)) ?

The solution to factor ((2x^4-6x^2+4x))/((6x^4-12x^3+6x^2)) is (x+2)/(3x)

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factor ((2x^4-6x^2+4x))/((6x^4-12x^3+6x^2))

factor

\frac{( 2 x ^{4} - 6 x ^{2} + 4 x )}{( 6 x ^{4} - 12 x ^{3} + 6 x ^{2} )}

\frac{x + 2}{3 x}

Solution steps

\frac{2 x ^{4} - 6 x ^{2} + 4 x}{6 x ^{4} - 12 x ^{3} + 6 x ^{2}}

Factor

2 x^{4} - 6 x^{2} + 4 x : 2 x (x^{3} - 3 x + 2)

= \frac{2 x ( x ^{3} - 3 x + 2 )}{6 x ^{4} - 12 x ^{3} + 6 x ^{2}}

Factor

6 x^{4} - 12 x^{3} + 6 x^{2} : 6 x^{2} (x^{2} - 2 x + 1)

= \frac{2 x ( x ^{3} - 3 x + 2 )}{6 x ^{2} ( x ^{2} - 2 x + 1 )}

Cancel

\frac{2 x ( x ^{3} - 3 x + 2 )}{6 x ^{2} ( x ^{2} - 2 x + 1 )} : \frac{x ^{3} - 3 x + 2}{3 x ( x ^{2} - 2 x + 1 )}

= \frac{x ^{3} - 3 x + 2}{3 x ( x ^{2} - 2 x + 1 )}

Factor

x^{3} - 3 x + 2 : (x - 1)^{2} (x + 2)

= \frac{( x - 1 ) ^{2} ( x + 2 )}{3 x ( x ^{2} - 2 x + 1 )}

Factor

3 x (x^{2} - 2 x + 1) : 3 x (x - 1)^{2}

= \frac{( x - 1 ) ^{2} ( x + 2 )}{3 x ( x - 1 ) ^{2}}

Cancel the common factor:

(x - 1)^{2}

= \frac{x + 2}{3 x}

- 9 w + 3 = 0

4 x^{3} - 3 x - 1 \geq 0

2 x + \frac{1}{3} + 1 < 4

x^{2} + 16 x - 22 = 0

3 x + 4 > \frac{1}{3} (x - 2)

What is factor ((2x^4-6x^2+4x))/((6x^4-12x^3+6x^2)) ?
The solution to factor ((2x^4-6x^2+4x))/((6x^4-12x^3+6x^2)) is (x+2)/(3x)