What are the solutions to the equation (2m+3)^2+6(2m+3)+5=0 ?

The solutions to the equation (2m+3)^2+6(2m+3)+5=0 are m=-2,m=-4

Find the zeros of (2m+3)^2+6(2m+3)+5=0

The zeros of (2m+3)^2+6(2m+3)+5=0 are m=-2,m=-4

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(2 m + 3)^{2} + 6 (2 m + 3) + 5 = 0

m = - 2, m = - 4

Solution steps

(2 m + 3)^{2} + 6 (2 m + 3) + 5 = 0

Expand

(2 m + 3)^{2} + 6 (2 m + 3) + 5 : 4 m^{2} + 24 m + 32

4 m^{2} + 24 m + 32 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 4 \cdot 32}{2 \cdot 4}

2 4^{2} - 4 \cdot 4 \cdot 32 = 8

m_{1, 2} = \frac{- 24 \pm 8}{2 \cdot 4}

Separate the solutions

m_{1} = \frac{- 24 + 8}{2 \cdot 4}, m_{2} = \frac{- 24 - 8}{2 \cdot 4}

m = \frac{- 24 + 8}{2 \cdot 4} : - 2

m = \frac{- 24 - 8}{2 \cdot 4} : - 4

The solutions to the quadratic equation are:

m = - 2, m = - 4

x^{2} = - 54

\frac{1}{x} + \frac{1}{x + 1} < \frac{2}{x + 6}

x^{4} - 9 x^{2} + 18

9.2 r + 5.514 = 158.234

- \frac{3}{2} x < 6 - (2 x - 5)

What are the solutions to the equation (2m+3)^2+6(2m+3)+5=0 ?
The solutions to the equation (2m+3)^2+6(2m+3)+5=0 are m=-2,m=-4
Find the zeros of (2m+3)^2+6(2m+3)+5=0
The zeros of (2m+3)^2+6(2m+3)+5=0 are m=-2,m=-4