What is factor 4x^2+20xy+25y^2 ?

The solution to factor 4x^2+20xy+25y^2 is (2x+5y)^2

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factor 4x^2+20xy+25y^2

factor

4 x^{2} + 20 x y + 25 y^{2}

(2 x + 5 y)^{2}

Solution steps

4 x^{2} + 20 x y + 25 y^{2}

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

4 x^{2} = (2 x)^{2}

25 y^{2} = (5 y)^{2}

20 x y = 2 \cdot 2 x \cdot 5 y

= (2 x)^{2} + 2 \cdot 2 x \cdot 5 y + (5 y)^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(2 x)^{2} + 2 \cdot 2 x \cdot 5 y + (5 y)^{2} = (2 x + 5 y)^{2}

= (2 x + 5 y)^{2}

\frac{24}{1.60218 \cdot 1 0 ^{- 19}}

\frac{2}{3} + \frac{3 t}{4} = \frac{31}{6}

64 x^{3} + 27 y^{3}

\frac{2 0 ^{0.4} - 1}{\frac{1060}{300} - 1}

- 2 + x < - x + 1

What is factor 4x^2+20xy+25y^2 ?
The solution to factor 4x^2+20xy+25y^2 is (2x+5y)^2