What are the solutions to the equation 4y^2-7y+5=3 ?

The solutions to the equation 4y^2-7y+5=3 are y=(7+sqrt(17))/8 ,y=(7-sqrt(17))/8

Find the zeros of 4y^2-7y+5=3

The zeros of 4y^2-7y+5=3 are y=(7+sqrt(17))/8 ,y=(7-sqrt(17))/8

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4 y^{2} - 7 y + 5 = 3

y = \frac{7 + 17}{8}, y = \frac{7 - 17}{8}

Decimal Notation

y = 1.39038 \dots, y = 0.35961 \dots

Solution steps

4 y^{2} - 7 y + 5 = 3

Move

3

to the left side

4 y^{2} - 7 y + 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 4 \cdot 2}{2 \cdot 4}

(- 7)^{2} - 4 \cdot 4 \cdot 2 = 17

y_{1, 2} = \frac{- ( - 7 ) \pm 17}{2 \cdot 4}

Separate the solutions

y_{1} = \frac{- ( - 7 ) + 17}{2 \cdot 4}, y_{2} = \frac{- ( - 7 ) - 17}{2 \cdot 4}

y = \frac{- ( - 7 ) + 17}{2 \cdot 4} : \frac{7 + 17}{8}

y = \frac{- ( - 7 ) - 17}{2 \cdot 4} : \frac{7 - 17}{8}

The solutions to the quadratic equation are:

y = \frac{7 + 17}{8}, y = \frac{7 - 17}{8}

\frac{2 3 - 3 2}{2}

\frac{x + 2}{4} = 7

1 - \frac{1}{4}

3 (2 x + 3) + 2 (x + 4) = 25

What are the solutions to the equation 4y^2-7y+5=3 ?
The solutions to the equation 4y^2-7y+5=3 are y=(7+sqrt(17))/8 ,y=(7-sqrt(17))/8
Find the zeros of 4y^2-7y+5=3
The zeros of 4y^2-7y+5=3 are y=(7+sqrt(17))/8 ,y=(7-sqrt(17))/8