What is (2+3i)^2+(2-3i)^2 ?

The solution to (2+3i)^2+(2-3i)^2 is -10

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simplify (2+3i)^2+(2-3i)^2

simplify

(2 + 3 i)^{2} + (2 - 3 i)^{2}

- 10

Solution steps

(2 + 3 i)^{2} + (2 - 3 i)^{2}

(2 + 3 i)^{2} = 12 i - 5

(2 - 3 i)^{2} = - 12 i - 5

= 12 i - 5 - 12 i - 5

Group like terms

= 12 i - 12 i - 5 - 5

Add similar elements:

12 i - 12 i = 0

= - 5 - 5

Subtract the numbers:

- 5 - 5 = - 10

= - 10

2 x - 3 (x + 5) = 2 x - (x + 3)

\frac{6 ^{\frac{1}{2}}}{6 ^{\frac{1}{3}}}

(\frac{( 30.03 + 0.21 )}{30.42}) - 1

x^{2} + 2 x = - 4

\frac{3}{4} + \frac{6}{5}