What is the answer to (3x-1)/9+x=(3x+1)/3+4 ?

The answer to (3x-1)/9+x=(3x+1)/3+4 is x= 40/3

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(3x-1)/9+x=(3x+1)/3+4

\frac{3 x - 1}{9} + x = \frac{3 x + 1}{3} + 4

x = \frac{40}{3}

Decimal Notation

x = 13.33333 \dots

Solution steps

\frac{3 x - 1}{9} + x = \frac{3 x + 1}{3} + 4

Multiply by LCM

12 x - 1 = 3 (3 x + 1) + 36

Expand

3 (3 x + 1) + 36 : 9 x + 39

12 x - 1 = 9 x + 39

Move

1

to the right side

12 x = 9 x + 40

Move

9 x

to the left side

3 x = 40

Divide both sides by

3

x = \frac{40}{3}

\frac{7 x - 1}{2 x - 3} \geq 2

lo g_{2} (M) + lo g_{2} (N) + 3

4 (3 a - b)^{2} + 20 (3 a - b) + 24

\frac{b}{6} + 5 = 13

\frac{3}{\frac{2}{2}}

What is the answer to (3x-1)/9+x=(3x+1)/3+4 ?
The answer to (3x-1)/9+x=(3x+1)/3+4 is x= 40/3
Solve for x: (3x-1)/9+x=(3x+1)/3+4
The solution is x= 40/3