What are the solutions to the equation -12x^2+36x=0 ?

The solutions to the equation -12x^2+36x=0 are x=0,x=3

Find the zeros of -12x^2+36x=0

The zeros of -12x^2+36x=0 are x=0,x=3

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- 12 x^{2} + 36 x = 0

x = 0, x = 3

Solution steps

- 12 x^{2} + 36 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 ( - 12 ) \cdot 0}{2 ( - 12 )}

3 6^{2} - 4 (- 12) \cdot 0 = 36

x_{1, 2} = \frac{- 36 \pm 36}{2 ( - 12 )}

Separate the solutions

x_{1} = \frac{- 36 + 36}{2 ( - 12 )}, x_{2} = \frac{- 36 - 36}{2 ( - 12 )}

x = \frac{- 36 + 36}{2 ( - 12 )} : 0

x = \frac{- 36 - 36}{2 ( - 12 )} : 3

The solutions to the quadratic equation are:

x = 0, x = 3

4 + 4 (2 x + 1) = - 4 (x + 4) - 2 x

\frac{1}{2} x - 2 \leq 3 x - \frac{3}{2}

x^{- \frac{5}{2}}

30 < 19 + x

y^{2} - 2 y + 4 = 0

What are the solutions to the equation -12x^2+36x=0 ?
The solutions to the equation -12x^2+36x=0 are x=0,x=3
Find the zeros of -12x^2+36x=0
The zeros of -12x^2+36x=0 are x=0,x=3