What are the solutions to the equation x^2-48=1 ?

The solutions to the equation x^2-48=1 are x=7,x=-7

Find the zeros of x^2-48=1

The zeros of x^2-48=1 are x=7,x=-7

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x^{2} - 48 = 1

x = 7, x = - 7

Solution steps

x^{2} - 48 = 1

Move

48

to the right side

x^{2} = 49

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 49, x = - 49

49 = 7

- 49 = - 7

x = 7, x = - 7

e^{4 l n (3)}

\frac{2}{7} 108 + 612

5 (4 z + 6) - 2 (z - 4) = 7 z (z + 4) - z (7 z - 2) - 48

- \frac{q}{7} \geq - 1

x^{2} + 12 x + 4 = 0

What are the solutions to the equation x^2-48=1 ?
The solutions to the equation x^2-48=1 are x=7,x=-7
Find the zeros of x^2-48=1
The zeros of x^2-48=1 are x=7,x=-7