What are the solutions to the equation -3x^2+17=113 ?

The solutions to the equation -3x^2+17=113 are x=4sqrt(2)i,x=-4sqrt(2)i

Find the zeros of -3x^2+17=113

The zeros of -3x^2+17=113 are x=4sqrt(2)i,x=-4sqrt(2)i

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- 3 x^{2} + 17 = 113

x = 42 i, x = - 42 i

Solution steps

- 3 x^{2} + 17 = 113

Move

17

to the right side

- 3 x^{2} = 96

Divide both sides by

- 3

x^{2} = - 32

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 32, x = - - 32

- 32 = 42 i

- - 32 = - 42 i

x = 42 i, x = - 42 i

3 x + x + 8 = 6 (x - 1)

3 x^{2} - 15 x - 42

35 \cdot 5

m^{2} = - 2 m + 8

5 + 3 x = - 22

What are the solutions to the equation -3x^2+17=113 ?
The solutions to the equation -3x^2+17=113 are x=4sqrt(2)i,x=-4sqrt(2)i
Find the zeros of -3x^2+17=113
The zeros of -3x^2+17=113 are x=4sqrt(2)i,x=-4sqrt(2)i