What are the solutions to the equation x^2-6x=1 ?

The solutions to the equation x^2-6x=1 are x=3+sqrt(10),x=3-sqrt(10)

Find the zeros of x^2-6x=1

The zeros of x^2-6x=1 are x=3+sqrt(10),x=3-sqrt(10)

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x^{2} - 6 x = 1

x = 3 + 10, x = 3 - 10

Decimal Notation

x = 6.16227 \dots, x = - 0.16227 \dots

Solution steps

x^{2} - 6 x = 1

Move

1

to the left side

x^{2} - 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 1) = 210

x_{1, 2} = \frac{- ( - 6 ) \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 10}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 10}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 10}{2 \cdot 1} : 3 + 10

x = \frac{- ( - 6 ) - 2 10}{2 \cdot 1} : 3 - 10

The solutions to the quadratic equation are:

x = 3 + 10, x = 3 - 10

6 x^{4} - 13 x^{3} - 70 x^{2} + 89 x + 60

3 ∣ 3 t + 1 ∣ = 2 ∣ 6 t + 3 ∣

6 > 2 k + 4

6 - 8

2 x^{2} + 13 x - 7 = 0

What are the solutions to the equation x^2-6x=1 ?
The solutions to the equation x^2-6x=1 are x=3+sqrt(10),x=3-sqrt(10)
Find the zeros of x^2-6x=1
The zeros of x^2-6x=1 are x=3+sqrt(10),x=3-sqrt(10)