What are the solutions to the equation 20^2+21^2=c^2 ?

The solutions to the equation 20^2+21^2=c^2 are c=29,c=-29

Find the zeros of 20^2+21^2=c^2

The zeros of 20^2+21^2=c^2 are c=29,c=-29

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2 0^{2} + 2 1^{2} = c^{2}

c = 29, c = - 29

Solution steps

2 0^{2} + 2 1^{2} = c^{2}

Switch sides

c^{2} = 2 0^{2} + 2 1^{2}

Simplify

2 0^{2} + 2 1^{2} : 841

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 841, c = - 841

841 = 29

- 841 = - 29

c = 29, c = - 29

- 9 - 5

17 x^{2} + 17 x = - 19

\frac{x}{6} + 7 = 12

\frac{1}{2} (3 + 5) 6

3 x^{2} - 6 x - 1 = 0

What are the solutions to the equation 20^2+21^2=c^2 ?
The solutions to the equation 20^2+21^2=c^2 are c=29,c=-29
Find the zeros of 20^2+21^2=c^2
The zeros of 20^2+21^2=c^2 are c=29,c=-29