What are the solutions to the equation x^2-x-26=0 ?

The solutions to the equation x^2-x-26=0 are x=(1+sqrt(105))/2 ,x=(1-sqrt(105))/2

Find the zeros of x^2-x-26=0

The zeros of x^2-x-26=0 are x=(1+sqrt(105))/2 ,x=(1-sqrt(105))/2

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x^{2} - x - 26 = 0

x = \frac{1 + 105}{2}, x = \frac{1 - 105}{2}

Decimal Notation

x = 5.62347 \dots, x = - 4.62347 \dots

Solution steps

x^{2} - x - 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 26 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 26) = 105

x_{1, 2} = \frac{- ( - 1 ) \pm 105}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 105}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 105}{2 \cdot 1}

x = \frac{- ( - 1 ) + 105}{2 \cdot 1} : \frac{1 + 105}{2}

x = \frac{- ( - 1 ) - 105}{2 \cdot 1} : \frac{1 - 105}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 105}{2}, x = \frac{1 - 105}{2}

9 x^{2} + 36 x + 37 = 0

4 - y \geq 9

y - 5 < - 4 or y - 5 \geq 1

n^{2} + 13 n + 22

d = (1 - (- 3))^{2} + (- 4 - (5))^{2}

What are the solutions to the equation x^2-x-26=0 ?
The solutions to the equation x^2-x-26=0 are x=(1+sqrt(105))/2 ,x=(1-sqrt(105))/2
Find the zeros of x^2-x-26=0
The zeros of x^2-x-26=0 are x=(1+sqrt(105))/2 ,x=(1-sqrt(105))/2