What is (7n}{3n-18}+\frac{n+3)/3 ?

The solution to (7n}{3n-18}+\frac{n+3)/3 is (n^2+4n-18)/(3(n-6))

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simplify (7n}{3n-18}+\frac{n+3)/3

simplify

\frac{7 n}{3 n - 18} + \frac{n + 3}{3}

\frac{n ^{2} + 4 n - 18}{3 ( n - 6 )}

Solution steps

\frac{7 n}{3 n - 18} + \frac{n + 3}{3}

Least Common Multiplier of

3 n - 18, 3 : 3 (n - 6)

Adjust Fractions based on the LCM

= \frac{7 n}{3 ( n - 6 )} + \frac{( n + 3 ) ( n - 6 )}{3 ( n - 6 )}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{7 n + ( n + 3 ) ( n - 6 )}{3 ( n - 6 )}

Simplify

7 n + (n + 3) (n - 6) : n^{2} + 4 n - 18

= \frac{n ^{2} + 4 n - 18}{3 ( n - 6 )}

3 x^{2} = 18

9 h - 7 (2 - h) < 8 (h + 11) + 8 h

9 \leq ∣ 7 - 8 n ∣

∣ 3 x - 1 ∣ < 13

\frac{- 1}{a - 2} + \frac{4}{4 - 2 a}

What is (7n}{3n-18}+\frac{n+3)/3 ?
The solution to (7n}{3n-18}+\frac{n+3)/3 is (n^2+4n-18)/(3(n-6))