What is 25+99+91v>=-92v+7(28v-90) ?

The solution to 25+99+91v>=-92v+7(28v-90) is v<= 58

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25+99+91v>=-92v+7(28v-90)

25 + 99 + 91 v \geq - 92 v + 7 (28 v - 90)

v \leq 58

Interval Notation

(- \infty, 58]

Solution steps

25 + 99 + 91 v \geq - 92 v + 7 (28 v - 90)

Add the numbers:

25 + 99 = 124

91 v + 124 \geq - 92 v + 7 (28 v - 90)

Expand

7 (28 v - 90) : 196 v - 630

91 v + 124 \geq - 92 v + 196 v - 630

Add similar elements:

- 92 v + 196 v = 104 v

91 v + 124 \geq 104 v - 630

Move

124

to the right side

91 v \geq 104 v - 754

Move

104 v

to the left side

- 13 v \geq - 754

Multiply both sides by

- 1

13 v \leq 754

Divide both sides by

13

v \leq 58

\frac{n - 2}{9 n - 54} - \frac{n - 4}{9 n - 54}

(4 x + 7) (x - 1) = (2 x - 1)^{2}

6 x^{2} - 54 x = 0

7 \cdot 7 \cdot 7 \cdot 7

lo g_{9} (81) = x

What is 25+99+91v>=-92v+7(28v-90) ?
The solution to 25+99+91v>=-92v+7(28v-90) is v<= 58