What are the solutions to the equation (3x-1)(x+2)=0 ?

The solutions to the equation (3x-1)(x+2)=0 are x= 1/3 ,x=-2

Find the zeros of (3x-1)(x+2)=0

The zeros of (3x-1)(x+2)=0 are x= 1/3 ,x=-2

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(3 x - 1) (x + 2) = 0

x = \frac{1}{3}, x = - 2

Decimal Notation

x = 0.33333 \dots, x = - 2

Solution steps

(3 x - 1) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 1 = 0 or x + 2 = 0

Solve

3 x - 1 = 0 : x = \frac{1}{3}

Solve

x + 2 = 0 : x = - 2

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 2

\frac{s - 10}{5} \geq 2

10 \geq 9 + 3

x^{3} - 3 x^{2} - 9 x + 27 \leq 0

5 x - 7 = 2 (x + 1)

2 \leq ∣ 3 x - 1 ∣ - 6

What are the solutions to the equation (3x-1)(x+2)=0 ?
The solutions to the equation (3x-1)(x+2)=0 are x= 1/3 ,x=-2
Find the zeros of (3x-1)(x+2)=0
The zeros of (3x-1)(x+2)=0 are x= 1/3 ,x=-2