What are the solutions to the equation -3x^2+6x-1=0 ?

The solutions to the equation -3x^2+6x-1=0 are x=(3-sqrt(6))/3 ,x=(3+sqrt(6))/3

Find the zeros of -3x^2+6x-1=0

The zeros of -3x^2+6x-1=0 are x=(3-sqrt(6))/3 ,x=(3+sqrt(6))/3

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- 3 x^{2} + 6 x - 1 = 0

x = \frac{3 - 6}{3}, x = \frac{3 + 6}{3}

Decimal Notation

x = 0.18350 \dots, x = 1.81649 \dots

Solution steps

- 3 x^{2} + 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 3 ) ( - 1 )}{2 ( - 3 )}

6^{2} - 4 (- 3) (- 1) = 26

x_{1, 2} = \frac{- 6 \pm 2 6}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 6}{2 ( - 3 )}, x_{2} = \frac{- 6 - 2 6}{2 ( - 3 )}

x = \frac{- 6 + 2 6}{2 ( - 3 )} : \frac{3 - 6}{3}

x = \frac{- 6 - 2 6}{2 ( - 3 )} : \frac{3 + 6}{3}

The solutions to the quadratic equation are:

x = \frac{3 - 6}{3}, x = \frac{3 + 6}{3}

\frac{15}{10} = \frac{x}{4}

∣ 2 x + 2 ∣ \geq 24

\frac{x - 5}{x - 7} > 0

8 x^{2} - 8 x - 16

(\frac{9 c ^{4}}{5 c})^{3}

What are the solutions to the equation -3x^2+6x-1=0 ?
The solutions to the equation -3x^2+6x-1=0 are x=(3-sqrt(6))/3 ,x=(3+sqrt(6))/3
Find the zeros of -3x^2+6x-1=0
The zeros of -3x^2+6x-1=0 are x=(3-sqrt(6))/3 ,x=(3+sqrt(6))/3