What are the solutions to the equation (x-2)(x+3)=6 ?

The solutions to the equation (x-2)(x+3)=6 are x=3,x=-4

Find the zeros of (x-2)(x+3)=6

The zeros of (x-2)(x+3)=6 are x=3,x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x - 2) (x + 3) = 6

x = 3, x = - 4

Solution steps

(x - 2) (x + 3) = 6

Expand

(x - 2) (x + 3) : x^{2} + x - 6

x^{2} + x - 6 = 6

Move

6

to the left side

x^{2} + x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 12) = 7

x_{1, 2} = \frac{- 1 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 7}{2 \cdot 1}, x_{2} = \frac{- 1 - 7}{2 \cdot 1}

x = \frac{- 1 + 7}{2 \cdot 1} : 3

x = \frac{- 1 - 7}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 3, x = - 4

7 = 6 v + 34 + 3 v

- 16 \geq 2 x - 4

x^{16} - y^{16}

\frac{x}{2} + 11 = - 1

3 x - 1 = 10

What are the solutions to the equation (x-2)(x+3)=6 ?
The solutions to the equation (x-2)(x+3)=6 are x=3,x=-4
Find the zeros of (x-2)(x+3)=6
The zeros of (x-2)(x+3)=6 are x=3,x=-4