What are the solutions to the equation s^2+5s+6=0 ?

The solutions to the equation s^2+5s+6=0 are s=-2,s=-3

Find the zeros of s^2+5s+6=0

The zeros of s^2+5s+6=0 are s=-2,s=-3

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s^{2} + 5 s + 6 = 0

s = - 2, s = - 3

Solution steps

s^{2} + 5 s + 6 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 6 = 1

s_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 5 + 1}{2 \cdot 1}, s_{2} = \frac{- 5 - 1}{2 \cdot 1}

s = \frac{- 5 + 1}{2 \cdot 1} : - 2

s = \frac{- 5 - 1}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

s = - 2, s = - 3

6.4 = 1.2 (4 + 2 x)

\frac{x + 1}{3} + 2 = 7

(- 4 + 4 i) (3 + 2 i)

x^{2} + 2 x + 1 = 4

\frac{8 x ^{5} y ^{6}}{4 x ^{6} y ^{4}}

What are the solutions to the equation s^2+5s+6=0 ?
The solutions to the equation s^2+5s+6=0 are s=-2,s=-3
Find the zeros of s^2+5s+6=0
The zeros of s^2+5s+6=0 are s=-2,s=-3