What are the solutions to the equation 11x^2=-5x^2-1 ?

The solutions to the equation 11x^2=-5x^2-1 are x= 1/4 i,x=-1/4 i

Find the zeros of 11x^2=-5x^2-1

The zeros of 11x^2=-5x^2-1 are x= 1/4 i,x=-1/4 i

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11 x^{2} = - 5 x^{2} - 1

x = \frac{1}{4} i, x = - \frac{1}{4} i

Solution steps

11 x^{2} = - 5 x^{2} - 1

Move

5 x^{2}

to the left side

16 x^{2} = - 1

Divide both sides by

16

x^{2} = - \frac{1}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{16}, x = - - \frac{1}{16}

- \frac{1}{16} = \frac{1}{4} i

- - \frac{1}{16} = - \frac{1}{4} i

x = \frac{1}{4} i, x = - \frac{1}{4} i

2 p + \frac{3}{4} q - 7 p + \frac{3}{2} q

- 1 \leq x \leq 4

s^{2} + 8 s + 15 = 0

x - 5 = 12

4 s^{2} + 36 s + 81 = 0

What are the solutions to the equation 11x^2=-5x^2-1 ?
The solutions to the equation 11x^2=-5x^2-1 are x= 1/4 i,x=-1/4 i
Find the zeros of 11x^2=-5x^2-1
The zeros of 11x^2=-5x^2-1 are x= 1/4 i,x=-1/4 i