What is factor 2n^2+19n+9 ?

The solution to factor 2n^2+19n+9 is (2n+1)(n+9)

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factor 2n^2+19n+9

factor

2 n^{2} + 19 n + 9

(2 n + 1) (n + 9)

Solution steps

2 n^{2} + 19 n + 9

Break the expression into groups

= (2 n^{2} + n) + (18 n + 9)

Factor out

n

from

2 n^{2} + n : n (2 n + 1)

Factor out

9

from

18 n + 9 : 9 (2 n + 1)

= n (2 n + 1) + 9 (2 n + 1)

Factor out common term

2 n + 1

= (2 n + 1) (n + 9)

x^{2} + 3 x - 2 = 2

(\frac{5}{2})^{10} ((\frac{5}{4})^{5})^{- 2}

∣ 3 x - 6 ∣ + 9 = 12

6 x + 5 x = - 11

(\frac{8}{3})^{- 2}