What is the answer to |2x|=2x^2+x-4 ?

The answer to |2x|=2x^2+x-4 is x=(-3-sqrt(41))/4 \lor x=(1+sqrt(33))/4

Solve for x: |2x|=2x^2+x-4

The solution is x=(-3-sqrt(41))/4 \lor x=(1+sqrt(33))/4

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∣ 2 x ∣ = 2 x^{2} + x - 4

x = \frac{- 3 - 41}{4} or x = \frac{1 + 33}{4}

Decimal Notation

x = - 2.35078 \dots, x = 1.68614 \dots

Solution steps

∣ 2 x ∣ = 2 x^{2} + x - 4

Find positive and negative intervals

x < 0, x \geq 0

Solve the inequality for each interval

x = \frac{- 3 - 41}{4} or x = \frac{1 + 33}{4}

\frac{15}{20}

2 k + 1 \geq 7

(\frac{5}{8})^{- 1}

(x^{2})^{\frac{3}{4}} \cdot x^{\frac{1}{2}}

3 x^{2} + 16 x - 12

What is the answer to |2x|=2x^2+x-4 ?
The answer to |2x|=2x^2+x-4 is x=(-3-sqrt(41))/4 \lor x=(1+sqrt(33))/4
Solve for x: |2x|=2x^2+x-4
The solution is x=(-3-sqrt(41))/4 \lor x=(1+sqrt(33))/4