What are the solutions to the equation 2x^2-9x=35 ?

The solutions to the equation 2x^2-9x=35 are x=7,x=-5/2

Find the zeros of 2x^2-9x=35

The zeros of 2x^2-9x=35 are x=7,x=-5/2

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2 x^{2} - 9 x = 35

x = 7, x = - \frac{5}{2}

Decimal Notation

x = 7, x = - 2.5

Solution steps

2 x^{2} - 9 x = 35

Move

35

to the left side

2 x^{2} - 9 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 ( - 35 )}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 (- 35) = 19

x_{1, 2} = \frac{- ( - 9 ) \pm 19}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 19}{2 \cdot 2}, x_{2} = \frac{- ( - 9 ) - 19}{2 \cdot 2}

x = \frac{- ( - 9 ) + 19}{2 \cdot 2} : 7

x = \frac{- ( - 9 ) - 19}{2 \cdot 2} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = 7, x = - \frac{5}{2}

3 n^{2} = 19

\frac{3}{9} \cdot \frac{3}{6}

\frac{π}{6} + \frac{π}{2}

23

What are the solutions to the equation 2x^2-9x=35 ?
The solutions to the equation 2x^2-9x=35 are x=7,x=-5/2
Find the zeros of 2x^2-9x=35
The zeros of 2x^2-9x=35 are x=7,x=-5/2