What are the solutions to the equation 126=3x^2+3x ?

The solutions to the equation 126=3x^2+3x are x=6,x=-7

Find the zeros of 126=3x^2+3x

The zeros of 126=3x^2+3x are x=6,x=-7

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126 = 3 x^{2} + 3 x

x = 6, x = - 7

Solution steps

126 = 3 x^{2} + 3 x

Switch sides

3 x^{2} + 3 x = 126

Move

126

to the left side

3 x^{2} + 3 x - 126 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 3 ( - 126 )}{2 \cdot 3}

3^{2} - 4 \cdot 3 (- 126) = 39

x_{1, 2} = \frac{- 3 \pm 39}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 3 + 39}{2 \cdot 3}, x_{2} = \frac{- 3 - 39}{2 \cdot 3}

x = \frac{- 3 + 39}{2 \cdot 3} : 6

x = \frac{- 3 - 39}{2 \cdot 3} : - 7

The solutions to the quadratic equation are:

x = 6, x = - 7

4 (w - 3) - 6 w = - 2 (w + 6)

- x^{2} - 2 x - 4 = 0

- 16 n + 12 = 39 - 7 n

x - 7 = - 5

49 \cdot 5

What are the solutions to the equation 126=3x^2+3x ?
The solutions to the equation 126=3x^2+3x are x=6,x=-7
Find the zeros of 126=3x^2+3x
The zeros of 126=3x^2+3x are x=6,x=-7