What are the solutions to the equation 3h^2+2h-16=0 ?

The solutions to the equation 3h^2+2h-16=0 are h=2,h=-8/3

Find the zeros of 3h^2+2h-16=0

The zeros of 3h^2+2h-16=0 are h=2,h=-8/3

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3 h^{2} + 2 h - 16 = 0

h = 2, h = - \frac{8}{3}

Decimal Notation

h = 2, h = - 2.66666 \dots

Solution steps

3 h^{2} + 2 h - 16 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 16 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 16) = 14

h_{1, 2} = \frac{- 2 \pm 14}{2 \cdot 3}

Separate the solutions

h_{1} = \frac{- 2 + 14}{2 \cdot 3}, h_{2} = \frac{- 2 - 14}{2 \cdot 3}

h = \frac{- 2 + 14}{2 \cdot 3} : 2

h = \frac{- 2 - 14}{2 \cdot 3} : - \frac{8}{3}

The solutions to the quadratic equation are:

h = 2, h = - \frac{8}{3}

3 (7 x - 4) = 93

- \frac{π}{2} - π

(x - 2)^{2} (x + 9) > 0

\frac{- 12 x ^{7} y ^{8}}{4 x ^{6} y ^{4}}

(\frac{π}{4}) + (\frac{π}{4})

What are the solutions to the equation 3h^2+2h-16=0 ?
The solutions to the equation 3h^2+2h-16=0 are h=2,h=-8/3
Find the zeros of 3h^2+2h-16=0
The zeros of 3h^2+2h-16=0 are h=2,h=-8/3