What are the solutions to the equation 4x^2+3x-12=0 ?

The solutions to the equation 4x^2+3x-12=0 are x=(-3+sqrt(201))/8 ,x=(-3-sqrt(201))/8

Find the zeros of 4x^2+3x-12=0

The zeros of 4x^2+3x-12=0 are x=(-3+sqrt(201))/8 ,x=(-3-sqrt(201))/8

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4 x^{2} + 3 x - 12 = 0

x = \frac{- 3 + 201}{8}, x = \frac{- 3 - 201}{8}

Decimal Notation

x = 1.39718 \dots, x = - 2.14718 \dots

Solution steps

4 x^{2} + 3 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 ( - 12 )}{2 \cdot 4}

3^{2} - 4 \cdot 4 (- 12) = 201

x_{1, 2} = \frac{- 3 \pm 201}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 3 + 201}{2 \cdot 4}, x_{2} = \frac{- 3 - 201}{2 \cdot 4}

x = \frac{- 3 + 201}{2 \cdot 4} : \frac{- 3 + 201}{8}

x = \frac{- 3 - 201}{2 \cdot 4} : \frac{- 3 - 201}{8}

The solutions to the quadratic equation are:

x = \frac{- 3 + 201}{8}, x = \frac{- 3 - 201}{8}

4^{\frac{3}{4}}

4 x + 1 - 1 \geq - 8

b^{3} - a^{3}

x^{2} - 13 x - 30

\frac{5 x + 2}{x - 6} \leq 1

What are the solutions to the equation 4x^2+3x-12=0 ?
The solutions to the equation 4x^2+3x-12=0 are x=(-3+sqrt(201))/8 ,x=(-3-sqrt(201))/8
Find the zeros of 4x^2+3x-12=0
The zeros of 4x^2+3x-12=0 are x=(-3+sqrt(201))/8 ,x=(-3-sqrt(201))/8