What is (x^2+6x)^{1/4}<2 ?

The solution to (x^2+6x)^{1/4}<2 is -8<x<=-6\lor 0<= x<2

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(x^2+6x)^{1/4}<2

(x^{2} + 6 x)^{\frac{1}{4}} < 2

- 8 < x \leq - 6 or 0 \leq x < 2

Interval Notation

(- 8, - 6] \cup [0, 2)

Solution steps

(x^{2} + 6 x)^{\frac{1}{4}} < 2

Take both sides of the equation to the power of

4

((x^{2} + 6 x)^{\frac{1}{4}})^{4} < 2^{4}

Simplify

x^{2} + 6 x < 16

x^{2} + 6 x < 16 : - 8 < x < 2

- 8 < x < 2

Find singularity points

Find non-negative values for radicals:

x \leq - 6 or x \geq 0

Combine the intervals

- 8 < x < 2 and (x \leq - 6 or x \geq 0)

Merge Overlapping Intervals

- 8 < x \leq - 6 or 0 \leq x < 2

- 3 x + 7 = 28

36 - z^{2} y^{2}

2 < ∣ c - 4 ∣

7 \geq 12 - g

3 x - 9 y + 9

What is (x^2+6x)^{1/4}<2 ?
The solution to (x^2+6x)^{1/4}<2 is -8<x<=-6\lor 0<= x<2