What are the solutions to the equation 2q^2+10q+12=q^2 ?

The solutions to the equation 2q^2+10q+12=q^2 are q=-5+sqrt(13),q=-5-sqrt(13)

Find the zeros of 2q^2+10q+12=q^2

The zeros of 2q^2+10q+12=q^2 are q=-5+sqrt(13),q=-5-sqrt(13)

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2 q^{2} + 10 q + 12 = q^{2}

q = - 5 + 13, q = - 5 - 13

Decimal Notation

q = - 1.39444 \dots, q = - 8.60555 \dots

Solution steps

2 q^{2} + 10 q + 12 = q^{2}

Move

q^{2}

to the left side

q^{2} + 10 q + 12 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 12 = 213

q_{1, 2} = \frac{- 10 \pm 2 13}{2 \cdot 1}

Separate the solutions

q_{1} = \frac{- 10 + 2 13}{2 \cdot 1}, q_{2} = \frac{- 10 - 2 13}{2 \cdot 1}

q = \frac{- 10 + 2 13}{2 \cdot 1} : - 5 + 13

q = \frac{- 10 - 2 13}{2 \cdot 1} : - 5 - 13

The solutions to the quadratic equation are:

q = - 5 + 13, q = - 5 - 13

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\frac{( x + 1 )}{6} - 2 x = \frac{( x ^{2} - 16 )}{9} - 8

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\frac{1}{2} π

6 x^{3} + 10 x^{2} + 3 x + 5

What are the solutions to the equation 2q^2+10q+12=q^2 ?
The solutions to the equation 2q^2+10q+12=q^2 are q=-5+sqrt(13),q=-5-sqrt(13)
Find the zeros of 2q^2+10q+12=q^2
The zeros of 2q^2+10q+12=q^2 are q=-5+sqrt(13),q=-5-sqrt(13)