What are the solutions to the equation (2/3)^2+(x)^2=1^2 ?

The solutions to the equation (2/3)^2+(x)^2=1^2 are x=(sqrt(5))/3 ,x=-(sqrt(5))/3

Find the zeros of (2/3)^2+(x)^2=1^2

The zeros of (2/3)^2+(x)^2=1^2 are x=(sqrt(5))/3 ,x=-(sqrt(5))/3

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(\frac{2}{3})^{2} + (x)^{2} = 1^{2}

x = \frac{5}{3}, x = - \frac{5}{3}

Decimal Notation

x = 0.74535 \dots, x = - 0.74535 \dots

Solution steps

(\frac{2}{3})^{2} + x^{2} = 1^{2}

Expand

(\frac{2}{3})^{2} + x^{2} : \frac{4}{9} + x^{2}

Expand

1^{2} : 1

\frac{4}{9} + x^{2} = 1

Move

\frac{4}{9}

to the right side

x^{2} = 1 - \frac{4}{9}

Simplify

1 - \frac{4}{9} : \frac{5}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{5}{9}, x = - \frac{5}{9}

\frac{5}{9} = \frac{5}{3}

- \frac{5}{9} = - \frac{5}{3}

x = \frac{5}{3}, x = - \frac{5}{3}

(x + 1) (x - 8)^{2} (x - 3) \geq 0

9 + \frac{3}{4} x = \frac{7}{8} x - 10

∣ x + 6 ∣ = ∣ 6 - x ∣

i^{87}

y^{2} + \frac{7}{4} y + \frac{49}{64} = 0

What are the solutions to the equation (2/3)^2+(x)^2=1^2 ?
The solutions to the equation (2/3)^2+(x)^2=1^2 are x=(sqrt(5))/3 ,x=-(sqrt(5))/3
Find the zeros of (2/3)^2+(x)^2=1^2
The zeros of (2/3)^2+(x)^2=1^2 are x=(sqrt(5))/3 ,x=-(sqrt(5))/3