What is the answer to 9x^2+79x-110=9x^2 ?

The answer to 9x^2+79x-110=9x^2 is x= 110/79

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9x^2+79x-110=9x^2

9 x^{2} + 79 x - 110 = 9 x^{2}

x = \frac{110}{79}

Decimal Notation

x = 1.39240 \dots

Solution steps

9 x^{2} + 79 x - 110 = 9 x^{2}

Subtract

9 x^{2}

from both sides

9 x^{2} + 79 x - 110 - 9 x^{2} = 9 x^{2} - 9 x^{2}

Simplify

79 x - 110 = 0

Move

110

to the right side

79 x = 110

Divide both sides by

79

x = \frac{110}{79}

x^{2} + 4 x + 4 = 1

(\frac{1}{9})^{- 3}

8 s + 1 = 5 s - 14

6 m + 5 > - 13 or - 7 m - 9 \geq 40

\frac{1}{2} \cdot 5

What is the answer to 9x^2+79x-110=9x^2 ?
The answer to 9x^2+79x-110=9x^2 is x= 110/79
Solve for x: 9x^2+79x-110=9x^2
The solution is x= 110/79