What are the solutions to the equation 2-x=x-(x^2)/2 ?

The solutions to the equation 2-x=x-(x^2)/2 are x=2

Find the zeros of 2-x=x-(x^2)/2

The zeros of 2-x=x-(x^2)/2 are x=2

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2 - x = x - \frac{x ^{2}}{2}

x = 2

Solution steps

2 - x = x - \frac{x ^{2}}{2}

Multiply both sides by

2

4 - 2 x = 2 x - x^{2}

Switch sides

2 x - x^{2} = 4 - 2 x

Move

2 x

to the left side

- x^{2} + 4 x = 4

Move

4

to the left side

- x^{2} + 4 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) ( - 4 )}{2 ( - 1 )}

4^{2} - 4 (- 1) (- 4) = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 ( - 1 )}

x = \frac{- 4}{2 ( - 1 )}

\frac{- 4}{2 ( - 1 )} = 2

x = 2

The solution to the quadratic equation is:

x = 2

6 - \frac{x}{2} + 2 \leq 4

2 x - (\frac{x - 1}{3}) = 1

\frac{5}{5 ^{\frac{1}{3}}}

0 \geq 3 x - 3 - 6

\frac{3 ^{9}}{3 ^{7}}

What are the solutions to the equation 2-x=x-(x^2)/2 ?
The solutions to the equation 2-x=x-(x^2)/2 are x=2
Find the zeros of 2-x=x-(x^2)/2
The zeros of 2-x=x-(x^2)/2 are x=2